简单公式 求改成大智慧L2能用的

 网友求助：

抄底: PSY.PSY<=25,STICK,COLORYELLOW,LINETHICK2;
STICKLINE(CROSS(PSY.PSY,30),0,1,2,0);

WZ1:=MA(CLOSE,5);
WZ2:=MA(CLOSE,10);
WZ3:=MA(CLOSE,20);
WZ5:=MA(CLOSE,60);
JD5:ATAN((WZ1/REF(WZ1,1)-1)*100)*57.3,NODRAW;
JD10:ATAN((WZ2/REF(WZ2,1)-1)*100)*57.3,NODRAW;
JD20:ATAN((WZ3/REF(WZ3,1)-1)*100)*57.3,NODRAW;
JD60:ATAN((WZ5/REF(WZ5,1)-1)*100)*57.3,NODRAW;

解答如下：

PSY:COUNT(CLOSE>REF(CLOSE,1),12)/12*100,LINETHICK0;
抄底: PSY<=25,STICK,COLORYELLOW,LINETHICK2;
STICKLINE(CROSS(PSY,30),0,1,8,0),COLOR00FFFF;
WZ1:=MA(CLOSE,5);
WZ2:=MA(CLOSE,10);
WZ3:=MA(CLOSE,20);
WZ5:=MA(CLOSE,60);
JD5:ATAN((WZ1/REF(WZ1,1)-1)*100)*57.3,LINETHICK0;
JD10:ATAN((WZ2/REF(WZ2,1)-1)*100)*57.3,LINETHICK0;
JD20:ATAN((WZ3/REF(WZ3,1)-1)*100)*57.3,LINETHICK0;
JD60:ATAN((WZ5/REF(WZ5,1)-1)*100)*57.3,LINETHICK0;
CROSS(JD60,10) AND JD10>20,LINETHICK2,COLORWHITE;